Asked by mike
find k so that the line through (3,k) and (1,-2) is parallel to 5x-3y=2. Find k so that the line is perpendicular to 3x+2y=6
Answers
Answered by
Reiny
I am glad you fixed up this question, since the way you had it a while back made no sense.
The new equation must differ only in the constant, since the slope is the same.
so the new equation must be
5x - 3y = c, but (1,-2) is supposed to be on it, so
5 + 6 = c = 11
new equation: 5x - 3y = 11
if (3,k) is on it also, ...
15 - 3k = 11
-3k = -4
k = 4/3
The new equation must differ only in the constant, since the slope is the same.
so the new equation must be
5x - 3y = c, but (1,-2) is supposed to be on it, so
5 + 6 = c = 11
new equation: 5x - 3y = 11
if (3,k) is on it also, ...
15 - 3k = 11
-3k = -4
k = 4/3
Answered by
mike
I am trying so hard I take what is given to me and try to study them. I have a problem with word problems and cannot figure out what I am doing wrong. I did my first two by myself just the other day and was so excited.I learned those problems from this site and got to utilize what was done for me so thanks
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