Asked by john
find all the local maxima and minima (the y-values) and the values of x where they occur.
g(x)=x^3-4x+1
g(x)=x^3-4x+1
Answers
Answered by
bobpursley
g'=3x^2-4=0
x= +- sqrt (3/4)
g''=6x at +sqrt (3/4) it is +, and at - sqrt (3/4) it is negative.
x= +- sqrt (3/4)
g''=6x at +sqrt (3/4) it is +, and at - sqrt (3/4) it is negative.
Answered by
john
so what is the local maxima and minima
Answered by
bobpursley
Well, this means you don't know any calculus.
So graph it, and read the values. Do it on your calculator.
So graph it, and read the values. Do it on your calculator.
Answered by
john
do you have an idea how i can find it
Answered by
Reiny
you called it pre-calc so I guess we can't use Calculus, too bad.
Do you have use of a programmable calculator?
Some classes now use those to solve your kind of question.
You could make a table of values, graph it, then by trial and error and a scientific calculator find the largest and smallest y values you can find.
hint: the min is just a little to the left of (1,-2), and the max is around (-1,4)
Do you have use of a programmable calculator?
Some classes now use those to solve your kind of question.
You could make a table of values, graph it, then by trial and error and a scientific calculator find the largest and smallest y values you can find.
hint: the min is just a little to the left of (1,-2), and the max is around (-1,4)
Answered by
john
yes i do the class i am in is pre calc
Answered by
john
is the minima x=1.15 y= -2.07
maxima x=-1.15 y=4.07
maxima x=-1.15 y=4.07
Answered by
Reiny
Yes, you are correct to one decimal accuracy.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.