Question

a ball of moist clay falls t the gournd from a height of 12m . It is in contact with the ground for 20.5 ms before coming to rest. What is the average acceleration of the clay during the time it is in contact with the ground?

Answer 1

Compute the speed of the clay when it hits the ground. It is
V = sqrt (2 g H)= 15.3 m/s
Divided that by the 0.0205 s that it takes to stop, and you will have the average deceleration rate as it deforms after hitting the ground.

I get 746 m/s^2 which is 76 g's

Answer 2

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