Asked by Anonymous

A ball of moist clay falls to the ground from a height of 19.8 m. It is in contact with the ground for 19.0 ms before coming to rest. What is the average acceleration of the clay during the time it is in contact with the ground? (Treat the ball as a particle.)
PLEASE HELP! :)
Answered by bobpursley
find the velocity just before impact.

vf^2=2g*h
solve for vf.

then, acceleration=(0-Vf)/timecontact

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