Okay, so I'm given this ODE:
(3xy-2y^2)dx - 7xydy = 0
I chose y = ux, so dy = udx + xdu
So subbing in for y I get:
(3(x^2)u - 2(x^2)(u^2))dx - 7(x^2)u(udx + xdu) = 0
3(x^2)udx - 3(x^2)(u^2)dx - 7(x^2)(u^2)dx - 7(x^3)udu = 0
3(x^2)udx - 9(x^2)(u^2)dx - 7(x^3)udu = 0
I do not know where to go from here in order to be able to integrate (i.e. separate the variables).