Asked by Anonymous
Find the area of a triangle with a base of 3 5/8 in. and a height of 2 1/2 in.
A)4 15/32 in 2 (sq)
B)8 1/16 in 2 (sq)
C)4 17/32 in 2 (sq)
D)8 17/32 in 2 (sq)
Help!! I am so confused.
A)4 15/32 in 2 (sq)
B)8 1/16 in 2 (sq)
C)4 17/32 in 2 (sq)
D)8 17/32 in 2 (sq)
Help!! I am so confused.
Answers
Answered by
MathMate
Area of triangle = (1/2)base*height
here we need to convert the mixed numbers (i.e. sum of number and fractions) to improper fractions (numerator is greater than the denominator) to facilitate the eventual multiplication:
base = 3 5/8 in. = (8*3+5)/8" = 29/8"
height = 2 1/2 in. =(2*2+1)/2" = 5/2"
Now calculate the area
A = (1/2)*(29/8)*(5/2)
=145/32 sq.in.
Convert the improper fraction into a mixed number and make your choice of the answers.
here we need to convert the mixed numbers (i.e. sum of number and fractions) to improper fractions (numerator is greater than the denominator) to facilitate the eventual multiplication:
base = 3 5/8 in. = (8*3+5)/8" = 29/8"
height = 2 1/2 in. =(2*2+1)/2" = 5/2"
Now calculate the area
A = (1/2)*(29/8)*(5/2)
=145/32 sq.in.
Convert the improper fraction into a mixed number and make your choice of the answers.
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