Question
the area of a rectangular garden is given by the trinomial x^3 + 6x - 27 what are the possible dimensions of a pool. use factoring
1. (x -9) and (x+3)
2. (x + 9) and (x-3)
3. (x -9) and (x-3)
4. (x +9) and (x+3)
1. (x -9) and (x+3)
2. (x + 9) and (x-3)
3. (x -9) and (x-3)
4. (x +9) and (x+3)
Answers
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So whats your final answer?
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the area of a rectangular classroom is given by the trinomial 10x^2 + 3x - 4 what are the possible dimensions of the classroom. use factoring
Answer
the area of a rectangular classroom is given by the trinomial 10x^2 + 3x - 4 what are the possible dimensions of the classroom. use factoring
1. (5x -4) and (2x + 1)
2. (5x -4) and (2x - 1)
3. (5x +4) and (2x - 1)
4. (5x + 4) and (2x + 1)
1. (5x -4) and (2x + 1)
2. (5x -4) and (2x - 1)
3. (5x +4) and (2x - 1)
4. (5x + 4) and (2x + 1)
Answered by
GPT 3.5
The correct answer is 3. (x - 9) and (x - 3)
To find the possible dimensions of the pool, we need to factor the trinomial x^3 + 6x - 27. By factoring, we get:
x^3 + 6x - 27 = (x - 3)(x^2 + 3x + 9) = (x - 3)(x - 3)(x + 3)
Therefore, the possible dimensions of the pool are (x - 9) and (x - 3).
To find the possible dimensions of the pool, we need to factor the trinomial x^3 + 6x - 27. By factoring, we get:
x^3 + 6x - 27 = (x - 3)(x^2 + 3x + 9) = (x - 3)(x - 3)(x + 3)
Therefore, the possible dimensions of the pool are (x - 9) and (x - 3).
Answered by
GPT 3.5
I apologize for the mistake in my previous response. Let's correct that.
To find the possible dimensions of the pool, we need to factor the trinomial x^3 + 6x - 27. By factoring, we get:
x^3 + 6x - 27 = (x - 3)(x^2 + 3x + 9)
To factor x^2 + 3x + 9, we need to use the quadratic formula:
x = (-b ± √(b^2 - 4ac))/(2a)
In this case, a = 1, b = 3, and c = 9:
x = (-3 ± √(3^2 - 4*9*1))/(2*1)
x = (-3 ± √(9 - 36))/2
x = (-3 ± √(-27))/2
x = (-3 ± 3√3i)/2
Since we have complex roots, the possible dimensions of the pool are not real numbers. Therefore, there are no real dimensions for the pool based on the factoring of the trinomial x^3 + 6x - 27.
To find the possible dimensions of the pool, we need to factor the trinomial x^3 + 6x - 27. By factoring, we get:
x^3 + 6x - 27 = (x - 3)(x^2 + 3x + 9)
To factor x^2 + 3x + 9, we need to use the quadratic formula:
x = (-b ± √(b^2 - 4ac))/(2a)
In this case, a = 1, b = 3, and c = 9:
x = (-3 ± √(3^2 - 4*9*1))/(2*1)
x = (-3 ± √(9 - 36))/2
x = (-3 ± √(-27))/2
x = (-3 ± 3√3i)/2
Since we have complex roots, the possible dimensions of the pool are not real numbers. Therefore, there are no real dimensions for the pool based on the factoring of the trinomial x^3 + 6x - 27.
Answered by
GPT 3.5
The final answer is that there are no real dimensions for the pool based on the factoring of the trinomial x^3 + 6x - 27.
Answered by
GPT 3.5
To find the possible dimensions of the classroom, we need to factor the trinomial 10x^2 + 3x - 4.
The factored form of 10x^2 + 3x - 4 is (5x - 2)(2x + 2).
Therefore, the possible dimensions of the classroom are 5x - 2 and 2x + 2.
The factored form of 10x^2 + 3x - 4 is (5x - 2)(2x + 2).
Therefore, the possible dimensions of the classroom are 5x - 2 and 2x + 2.
Answered by
GPT 3.5
To find the possible dimensions of the classroom, we need to factor the trinomial 10x^2 + 3x - 4.
The factored form of 10x^2 + 3x - 4 is (5x - 4)(2x + 1).
Therefore, the possible dimensions of the classroom are 5x - 4 and 2x + 1.
So, the correct choice is:
2. (5x - 4) and (2x - 1)
The factored form of 10x^2 + 3x - 4 is (5x - 4)(2x + 1).
Therefore, the possible dimensions of the classroom are 5x - 4 and 2x + 1.
So, the correct choice is:
2. (5x - 4) and (2x - 1)
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