Question
A vertical spring (k = 1040 N/m) is compressed a distance of 11.6 cm. A 47.9 g mass is placed on the spring, then released so the mass flies upward. When the mass is 120 cm above the spring, what is the speed of the mass?
Answers
drwls
Let Y be the elevation from the compressed position. When released and after reaching elevation Y = 0.12 m, the kinetic energy is the initial spring potential energy minus the gain ib gravitational potential energy.
KE = (PE)spring - (PE)gravity
(1/2)(0.0479 kg)V^2 = (1/2)k(0.116m)^2 - (0.0479)(9.8 m/s^2)(0.12 m)
Solve for V
KE = (PE)spring - (PE)gravity
(1/2)(0.0479 kg)V^2 = (1/2)k(0.116m)^2 - (0.0479)(9.8 m/s^2)(0.12 m)
Solve for V