Asked by Anonymous
how many grams of water must be added to 75.5 grams of Ca(NO3)2 to for a 0.500 m solution
Answers
Answered by
bobpursley
m as in molality? Normally this question is Molarity.
molality= molesSolute/kg of water
.5= moles/1000*grams water
gramswater= 75.5g/(molmass*1000*.5)
solve for grams water.
molality= molesSolute/kg of water
.5= moles/1000*grams water
gramswater= 75.5g/(molmass*1000*.5)
solve for grams water.
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