Asked by alex
How many grams of water when supplied with 348 J of heat will gain a temperature of 5.2oC?
Answers
Answered by
DrBob222
q = mcdT.
348 = m*4.184 J/oC*5.2
Solve for m in grams.
348 = m*4.184 J/oC*5.2
Solve for m in grams.
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