its 20celcius outside whats the f if f=(9/5 x c)+32 what is this

a)62deg
b)68deg
c)78deg
d)93 3/5 deg

2 answers

I will start it for you:

f= 9c/5 + 32
f= 9*20/5 + 32
f= 9*4+32
9/5 * 20) + 32 =

(180/5) + 32 =
36 + 32 = 68