To solve this system of equations, we can use the elimination method.
First, we can multiply the first equation by 5 and the second equation by 3 to make the coefficients of x in both equations equal:
15x + 30y = 105
- 15x + 6y = 39
Now, we can add these two equations together to eliminate x:
36y = 144
y = 4
Now that we have solved for y, we can substitute y = 4 back into the first original equation to solve for x:
3x + 6(4) = 21
3x + 24 = 21
3x = -3
x = -1
Therefore, the solution to this system of equations is x = -1 and y = 4.
Solve the system of equations.
3x + 6y = 21
- 5x + 2y = 13 (1 point)
1 answer