Question

The roof on a house rises 1.50 m over a horizontal diestance of 3.50 m. A 72.9-kg roofer stands on the roof. Is the frictional force that keeps the roofer from slipping equal in magnitude to F perpendicular or F paralell?

What is its magnitude?

Answer 1

Neither. Friction force is parallel, but it is equal to mu*Fperpendicular which is mu*mg*CosineTheta

cosine theta= 3.5/(sqrt(1.5^2+3.5^2))

Answer 2

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