Asked by Debra
write each of the following in the indicated base.
1011two to base ten
1574 to base twelve
MCMLIV to base ten
1011two to base ten
1574 to base twelve
MCMLIV to base ten
Answers
Answered by
Reiny
1011two to base ten
= 1(2^3) + 0(2^2) + 1(2) + 1
= 11
1574 to base twelve
powers of 12:
12, 144, 1728 , ...
1574/144 = 10 with remainder of 134
134/12 = 11 with remainder of 2
so 1574 = 10(12)^2 + 11(12) + 2
= AB2 in base 12
= 1(2^3) + 0(2^2) + 1(2) + 1
= 11
1574 to base twelve
powers of 12:
12, 144, 1728 , ...
1574/144 = 10 with remainder of 134
134/12 = 11 with remainder of 2
so 1574 = 10(12)^2 + 11(12) + 2
= AB2 in base 12
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