Question

I'm not sure how to solve this problem, but the answer's -12

e^(x-6)=(1/e^2)^(X+6)

Thanks :D

Answer 1

The right hand side can be transformed to (e^-2)^(x+6)
=e^(-2(x+6))

Now both left- and right-hand sides are to the base e, you can take the natural logarithms of each side.
Using ln(e^y)=y, you will end up with a linear equation with x as the unknown.
I do not get -12 as the solution of x.

You can post what you get for checking.

Answer 2

A nurse wants to add water to 38 ounces of a 10% solution of benzalkonium chloride to dilute it to an 8% solution. How much water must she add? (Hint: Water is 0% benzalkonium chloride.)