Asked by sam
Find the resulting displacement of a 15-km displacement and a 25-km displacement when the angle between them is 90 degrees.( Your answer should include magnitude and direction of the displacement.)
Answers
Answered by
AE
To find the resultant, separate each of the vectors into x and y components so it should be:
v1: 15x + 0y
v2: 0x + 25 y
add those together and the resultant vector is:
resultant vector: 15x + 25y
to get the magnitude, you do the square root of the x-comp squared plus the y-comp squared so its
15^2+25^2 and then square root that and you should get a magnitude of about 29 km
for the direction of displacement, or the angle, you do tan(angle)=ycomp/xcomp so angle=inversetan(25/15) and you should get about 59 degrees north of east
v1: 15x + 0y
v2: 0x + 25 y
add those together and the resultant vector is:
resultant vector: 15x + 25y
to get the magnitude, you do the square root of the x-comp squared plus the y-comp squared so its
15^2+25^2 and then square root that and you should get a magnitude of about 29 km
for the direction of displacement, or the angle, you do tan(angle)=ycomp/xcomp so angle=inversetan(25/15) and you should get about 59 degrees north of east
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