Question

At the instant oxygen is reacting at the rate 5.0 x 10-4 mol/L*s, at what rate is NO reacting and NO2 forming?

this is a method of initial rate problem. i don't know what to do

the chemical equation is
2 NO(g) + O2 (g) ---> 2 NO2 (g)

Answer 1

Both of them have a 2 as a coefficent, so wouldn't the rate be twice that of O2?

Answer 2

i see what your saying. so multiply the rate by two to get the rate of NO? but what is NO2 forming

Answer 3

Won't the rate of disappearance of NO be the same as the rate of formation of NO2 since both of the coefficients are the same?