Asked by Anonymous

A sports car of mass 1400 kg (including the driver) crosses the rounded top of a hill (radius = 93 m) at 27 m/s.
1) Determine the normal force exerted by the road on the car.
2) Determine the normal force exerted by the car on the 75 kg driver.
3) Determine the car speed at which the normal force on the driver equals zero.
Answered by bobpursley
I will be happy to critique your thinking.
Answered by Anonymous
I can't seem to get past the first question. I tried squaring the velocity, dividing that by the radius, and then multiplying all of that by the weight of the car. That answer wasn't right.
Answered by bobpursley
Of course it isn't right. Why did you multiply centripetal acceleration by a force?
It idea is to look at the net force downward by the car.
Answered by Joe Biden
Interesting. Use the centrifugal equation and multiply it with the third derivative of the acceleration formula you have memorized.
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