Asked by bob
A family car has a mass of 1400 kg. In an accident it hits a wall and goes from a speed of 27 m/s to a standstill in 1.5 seconds. By how much would the force have been reduced if the car had had a crumple zone that increased the collision time to 2.2 seconds?
Answers
Answered by
Anonymous
p = momentum = 1400 * 27 = 37800 kg m/s
force = change in momentum / change in time
first one F1 = 37800 / 1.5 = 25200 Newtons
second one F2 = 37800 / 2.2 = 17182 Newtons
subtract
force = change in momentum / change in time
first one F1 = 37800 / 1.5 = 25200 Newtons
second one F2 = 37800 / 2.2 = 17182 Newtons
subtract
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