To find the perimeter of the rectangle, we need to find the length of each side and add them up.
Side AB:
Using the distance formula,
AB = sqrt((4-1)^2 + (7-7)^2) = sqrt(3^2 + 0) = sqrt(9) = 3
Side BC:
Using the distance formula,
BC = sqrt((4-4)^2 + (-4-7)^2) = sqrt(0 + 121) = sqrt(121) = 11
Side CD:
Using the distance formula,
CD = sqrt((1-4)^2 + (-4+4)^2) = sqrt((-3)^2 + 0) = sqrt(9) = 3
Side DA:
Using the distance formula,
DA = sqrt((1-1)^2 + (-4-7)^2) = sqrt(0 + 121) = sqrt(121) = 11
Adding up all the sides:
Perimeter = AB + BC + CD + DA
Perimeter = 3 + 11 + 3 + 11
Perimeter = 28
Therefore, the perimeter of rectangle ABCD is 28 units.
Find the perimeter of rectangle ABCD, with vertices A(1,7), B(4,7), C(4,−4), and D(1,−4).(1 point)
1 answer