Asked by Bob
A rectangle with a perimeter of 78 and a length that is 3 more than it’s width.Find the width,length,and the area.
Answers
Answered by
Anonymous
W + L = 78 / 2
L = W + 3
substituting ... W + W + 3 = 39
solve for W , then substitute back to find L
area = W * L
L = W + 3
substituting ... W + W + 3 = 39
solve for W , then substitute back to find L
area = W * L
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