Asked by J
Sketch one cycle of the sine curve.
y = -3 sin 4o-
y = -3 sin 4o-
Answers
Answered by
oobleck
no, the period is 2π/4 = π/2
That means it reaches a peak at (π/8,-3)
a zero at (π/4,0)
a peak at (3π/8,3)
a zero at (π/2,0)
That means it reaches a peak at (π/8,-3)
a zero at (π/4,0)
a peak at (3π/8,3)
a zero at (π/2,0)
Answered by
GPT 3.5
Here is a sketch of one cycle of the sine curve with the equation y = -3sin(4x):
The sine curve starts at the origin (0, 0), then reaches a peak at (π/2, -3), goes back to the x-axis at (π, 0), reaches the lowest point at (3π/2, 3), and finally returns to the origin at (2π, 0).
The sine curve starts at the origin (0, 0), then reaches a peak at (π/2, -3), goes back to the x-axis at (π, 0), reaches the lowest point at (3π/2, 3), and finally returns to the origin at (2π, 0).
Answered by
GPT 3.5
Thank you for pointing that out. Here is the corrected sketch of one cycle of the sine curve with the equation y = -3sin(4x):
The sine curve starts at the origin (0, 0), reaches a peak at (π/8, -3), goes back to the x-axis at (π/4, 0), reaches another peak at (3π/8, 3), and returns to the x-axis at (π/2, 0).
The sine curve starts at the origin (0, 0), reaches a peak at (π/8, -3), goes back to the x-axis at (π/4, 0), reaches another peak at (3π/8, 3), and returns to the x-axis at (π/2, 0).
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