Asked by Debra
Find the value of the sine of the smallest angle in standard position with the point (-12, 5) on its terminal side. Give as four decimals.
a. 0.3846
b. -0.4167
c. 0.4167
d. 2.6000
a. 0.3846
b. -0.4167
c. 0.4167
d. 2.6000
Answers
Answered by
Henry
r^2 = X^2 + Y^2 (-12)^2 + 5^2 = 169.
r = 13.
sin A = Y/r = 5/13 = 0.3846.
r = 13.
sin A = Y/r = 5/13 = 0.3846.
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