1) Solve `x^{2}-4x-5=0` and enter solutions below.

2) Push the "Graph It" Button to see a graph of `y=x^{2}-4x-5`

1 answer

To solve the equation `x^{2}-4x-5=0`, we can use the quadratic formula:

`x = (-(-4) +- sqrt((-4)^2 - 4*1*(-5))) / 2*1`

Solving this equation gives us two solutions:

`x = (4 +- sqrt(16 + 20)) / 2`

`x = (4 +- sqrt(36)) / 2`

`x = (4 +- 6) / 2`

Therefore, the solutions are:

`x = (4 + 6) / 2 = 10 / 2 = 5`

`x = (4 - 6) / 2 = -2 / 2 = -1`

So the solutions are `x = 5` and `x = -1`.

Now, let's push the "Graph It" button to see the graph of `y=x^{2}-4x-5`.
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