Solve the system of equations.3x−4y=40 5x−5y=55 (1 point)Responses(8,−3) left parenthesis 8 comma negative 3 right parenthesis(14, 3) left parenthesis 14 comma 3 right parenthesis(4,−7)left parenthesis 4 comma negative 7 right parenthesis(18, 7)

Answer 1

To solve this system of equations, we can use either substitution or elimination method.

Let's use the elimination method:
1. Multiply the first equation by 5 and the second equation by 3 to make the coefficients of y the same:
15x - 20y = 200
15x - 15y = 165

2. Subtract the second equation from the first:
-5y = 35
y = -7

3. Substitute y = -7 into either equation to solve for x:
3x - 4(-7) = 40
3x + 28 = 40
3x = 12
x = 4

Therefore, the solution to the system of equations is (4, -7).
So the correct response is (4, -7).