Asked by Julia

using the work-kinetic energy theorem:

.5mvo^2 + Fo/c = .5 mv1^2 where v1 is the velocity at x max I got the following but it is not formatted proprerly. Where am I wrong?

.5vo^2 +Fo/c*m = .5v1^2
vo^2 + 2Fo/c*m = v1^2
sqrt (vo^2 + 2Fo/c*m) = v1

Answers

Answered by bobpursley
What is c?
Answered by Julia
m to the -1 power
Answered by Julia
c= m to the -1 power
Answered by bobpursley
then I don't understand your second term:

Fo/c*m if c= m^-1, then
Fo/(1/m *m)=Fo

which is not right. YOu cant add Fo to KE to have work energy.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions