Question
using the work-kinetic energy theorem:
.5mvo^2 + Fo/c = .5 mv1^2 where v1 is the velocity at x max I got the following but it is not formatted proprerly. Where am I wrong?
.5vo^2 +Fo/c*m = .5v1^2
vo^2 + 2Fo/c*m = v1^2
sqrt (vo^2 + 2Fo/c*m) = v1
.5mvo^2 + Fo/c = .5 mv1^2 where v1 is the velocity at x max I got the following but it is not formatted proprerly. Where am I wrong?
.5vo^2 +Fo/c*m = .5v1^2
vo^2 + 2Fo/c*m = v1^2
sqrt (vo^2 + 2Fo/c*m) = v1
Answers
bobpursley
What is c?
Julia
m to the -1 power
Julia
c= m to the -1 power
bobpursley
then I don't understand your second term:
Fo/c*m if c= m^-1, then
Fo/(1/m *m)=Fo
which is not right. YOu cant add Fo to KE to have work energy.
Fo/c*m if c= m^-1, then
Fo/(1/m *m)=Fo
which is not right. YOu cant add Fo to KE to have work energy.