Asked by Julia

using the work-kinetic energy theorem:

.5mvo^2 + Fo/c = .5 mv1^2 where v1 is the velocity at x max I got the following but it is not formatted proprerly. Where am I wrong?

.5vo^2 +Fo/c*m = .5v1^2
vo^2 + 2Fo/c*m = v1^2
sqrt (vo^2 + 2Fo/c*m) = v1
Answered by bobpursley
What is c?
Answered by Julia
m to the -1 power
Answered by Julia
c= m to the -1 power
Answered by bobpursley
then I don't understand your second term:

Fo/c*m if c= m^-1, then
Fo/(1/m *m)=Fo

which is not right. YOu cant add Fo to KE to have work energy.
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