Asked by yes

Find the mean absolute deviation of the following dataset.

{21,25,25,26,26,27,28,30}(1 point)
The mean absolute deviation is
.

Answers

Answered by yes
wrong
Answered by yes
also wrong
Answered by GPT 3.5
3.125.

To find the mean absolute deviation, first calculate the mean of the dataset by adding up all the numbers and dividing by the total count of numbers:
(21+25+25+26+26+27+28+30) / 8 = 27.

Next, subtract the mean from each number in the dataset and find the absolute value of each difference:
|21-27| = 6
|25-27| = 2
|25-27| = 2
|26-27| = 1
|26-27| = 1
|27-27| = 0
|28-27| = 1
|30-27| = 3

Then, calculate the average of these absolute differences:
(6+2+2+1+1+0+1+3) / 8 = 3.125.

Therefore, the mean absolute deviation of the dataset is 3.125.
Answered by GPT 3.5
I apologize for the error.

To find the mean absolute deviation, first calculate the mean of the dataset by adding up all the numbers and dividing by the total count of numbers:
(21+25+25+26+26+27+28+30) / 8 = 26.5

Next, subtract the mean from each number in the dataset and find the absolute value of each difference:
|21-26.5| = 5.5
|25-26.5| = 1.5
|25-26.5| = 1.5
|26-26.5| = 0.5
|26-26.5| = 0.5
|27-26.5| = 0.5
|28-26.5| = 1.5
|30-26.5| = 3.5

Then, calculate the average of these absolute differences:
(5.5+1.5+1.5+0.5+0.5+0.5+1.5+3.5) / 8 = 1.875

Therefore, the mean absolute deviation of the dataset is 1.875.
Answered by GPT 3.5
I apologize for the mistake. Let's correct the calculation.

To find the mean absolute deviation, first calculate the mean of the dataset by adding up all the numbers and dividing by the total count of numbers:
(21+25+25+26+26+27+28+30) / 8 = 26.5

Next, subtract the mean from each number in the dataset and find the absolute value of each difference:
|21-26.5| = 5.5
|25-26.5| = 1.5
|25-26.5| = 1.5
|26-26.5| = 0.5
|26-26.5| = 0.5
|27-26.5| = 0.5
|28-26.5| = 1.5
|30-26.5| = 3.5

Then, calculate the average of these absolute differences:
(5.5+1.5+1.5+0.5+0.5+0.5+1.5+3.5) / 8 = 2.125

Therefore, the mean absolute deviation of the dataset is 2.125. Thank you for your patience.

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