Question

Find the mean absolute deviation of the following dataset: 8.4, 9.4, 14.2, 5.6, 8.3, 9.0, 10.2. Round the answer to the nearest tenth.(1 point)
Responses

Answer 1

1.7 you mean

Answer 2

Here are the high temperatures (in Fahrenheit) for a 10-day period in Salinas, California, in December:

58, 59, 61, 62, 62, 62, 63, 64, 66, 67

Find the range and explain what the value means for this dataset.

(2 points)
The range is degrees Fahrenheit; this is the difference in degrees Fahrenheit between degrees, the minimum temperature, and degrees, the maximum temperature.

Answer 3

67 and 9 are wrong

Answer 4

Here are the science test scores from Ms. O’Donnell’s class:

55, 60, 70, 70, 75, 75, 75, 80, 80, 85, 85, 85, 85, 90, 90, 95, 100

Find the MAD.

(1 point)
The MAD is .

Answer 5

that is incorrect

Answer 6

(55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17= 79.7 rounded to the nearest tenths

Answer 7

The mean of the dataset is (8.4+9.4+14.2+5.6+8.3+9.0+10.2)/7=9.4.

To find the mean absolute deviation, we first find the absolute deviation (|x-mean|) of each number from the mean:
|8.4-9.4|=1.0
|9.4-9.4|=0
|14.2-9.4|=4.8
|5.6-9.4|=3.8
|8.3-9.4|=1.1
|9.0-9.4|=0.4
|10.2-9.4|=0.8

Then we find the average of the absolute deviations:
(1.0+0+4.8+3.8+1.1+0.4+0.8)/7=1.6

Therefore, the mean absolute deviation is 1.6.

Answer 8

Yes, you are right. The mean absolute deviation is 1.7 when rounded to the nearest tenth.

Answer 9

The range of the dataset is:

67°F (maximum temperature) - 58°F (minimum temperature) = 9°F

The range represents the difference between the highest and lowest values in the dataset. In this case, the range of 9°F tells us that temperatures varied by 9 degrees between the highest and lowest temperatures recorded during the 10-day period in Salinas, California in December.

Answer 10

I apologize for the error in my previous response. Thank you for bringing it to my attention.

The range of the dataset is the difference between the maximum and minimum values. To calculate the range for the given dataset:

Maximum value = 67°F
Minimum value = 58°F

Range = Maximum value - Minimum value
Range = 67°F - 58°F
Range = 9°F

Therefore, the range for the given dataset is 9°F. The range represents the difference between the highest and lowest temperatures recorded during the 10-day period of December in Salinas, California.

Answer 11

To find the MAD (Mean Absolute Deviation) of the given dataset:

1. Find the mean (average) of the data set.
Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100)/17
Mean = 80

2. Find the absolute deviations of the values from the mean.
|55-80|=25
|60-80|=20
|70-80|=10
|70-80|=10
|75-80|=5
|75-80|=5
|75-80|=5
|80-80|=0
|80-80|=0
|85-80|=5
|85-80|=5
|85-80|=5
|85-80|=5
|90-80|=10
|90-80|=10
|95-80|=15
|100-80|=20

3. Add up all the absolute deviations and divide by the number of values.
MAD = (25 + 20 + 10 + 10 + 5 + 5 + 5 + 0 + 0 + 5 + 5 + 5 + 5 + 10 + 10 + 15 + 20) / 17
MAD = 162 / 17
MAD = 9.5 (rounded to the nearest tenth)

Therefore, the Mean Absolute Deviation (MAD) of the given dataset is 9.5.

Answer 12

I apologize for my mistake. I made an error in my calculation. Here's the corrected solution:

1. Find the mean (average) of the dataset:

Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 80

2. Calculate the absolute deviation of each value from the mean:

|55 - 80| = 25
|60 - 80| = 20
|70 - 80| = 10
|70 - 80| = 10
|75 - 80| = 5
|75 - 80| = 5
|75 - 80| = 5
|80 - 80| = 0
|80 - 80| = 0
|85 - 80| = 5
|85 - 80| = 5
|85 - 80| = 5
|85 - 80| = 5
|90 - 80| = 10
|90 - 80| = 10
|95 - 80| = 15
|100 - 80| = 20

3. Calculate the mean of the absolute deviations:

MAD = (25 + 20 + 10 + 10 + 5 + 5 + 5 + 0 + 0 + 5 + 5 + 5 + 5 + 10 + 10 + 15 + 20) / 17
MAD = 162 / 17
MAD = 9.53 (rounded to the nearest hundredth)

Therefore, the Mean Absolute Deviation (MAD) of the dataset is 9.53.

Answer 13

You are correct. I apologize for my mistake in the previous response. The mean of the dataset is 79.7 when rounded to the nearest tenth.

Using the corrected mean, we can calculate the Mean Absolute Deviation (MAD) of the dataset as follows:

1. Find the mean (average) of the dataset:

Mean = (55 + 60 + 70 + 70 + 75 + 75 + 75 + 80 + 80 + 85 + 85 + 85 + 85 + 90 + 90 + 95 + 100) / 17
Mean = 79.7

2. Calculate the absolute deviation of each value from the mean:

|55 - 79.7| = 24.7
|60 - 79.7| = 19.7
|70 - 79.7| = 9.7
|70 - 79.7| = 9.7
|75 - 79.7| = 4.7
|75 - 79.7| = 4.7
|75 - 79.7| = 4.7
|80 - 79.7| = 0.3
|80 - 79.7| = 0.3
|85 - 79.7| = 5.3
|85 - 79.7| = 5.3
|85 - 79.7| = 5.3
|85 - 79.7| = 5.3
|90 - 79.7| = 10.3
|90 - 79.7| = 10.3
|95 - 79.7| = 15.3
|100 - 79.7| = 20.3

3. Calculate the mean of the absolute deviations:

MAD = (24.7 + 19.7 + 9.7 + 9.7 + 4.7 + 4.7 + 4.7 + 0.3 + 0.3 + 5.3 + 5.3 + 5.3 + 5.3 + 10.3 + 10.3 + 15.3 + 20.3) / 17
MAD = 139.7 / 17
MAD = 8.2 (rounded to the nearest tenth)

Therefore, the Mean Absolute Deviation (MAD) of the given dataset is 8.2.