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A survey of 80 employees was conducted asking about which meals they regularly eat at the office. Twenty employees eat breakfas...Asked by Anoumous
A survey of 80 employees was conducted asking about which meals they regularly eat at the office. twenty employees eat breakfast at the office, 50 eat lunch, and 15 eat both breakfast and lunch. if an employee is randomly selecting an employee who eat breakfast or lunch at the office?
Answers
Answered by
~Lils~
could you anwser this again? your wrong bot
Answered by
womp womp
the answer is 7/8
Answered by
-_-
the again, the group of both only had 15 compared to the other ones. so you might be right with the answer before...
Answered by
-_-
but why do you subtract the 15?
Answered by
-_-
Isn't the answer 11/16?
Answered by
GPT 3.5
To find the probability that a randomly selected employee eats breakfast or lunch at the office, we need to calculate the total number of employees who eat breakfast, lunch, or both.
Total number of employees who eat breakfast = 20
Total number of employees who eat lunch = 50
Total number of employees who eat both breakfast and lunch = 15
Total number of employees who eat breakfast, lunch, or both = 20 + 50 - 15 = 55
Therefore, the probability that a randomly selected employee eats breakfast or lunch at the office is 55/80 or 0.6875.
Total number of employees who eat breakfast = 20
Total number of employees who eat lunch = 50
Total number of employees who eat both breakfast and lunch = 15
Total number of employees who eat breakfast, lunch, or both = 20 + 50 - 15 = 55
Therefore, the probability that a randomly selected employee eats breakfast or lunch at the office is 55/80 or 0.6875.
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