Question
There are 100 employees in a room. 99% are managers. How many managers must leave the room to bring down the percentage of managers to 98%?
Answers
Reiny
Right now there are 99 managers.
(99 - x)/(100-x) =98/100
9900-100x = 9800-98x
-2x = -100
x = 50
check:
now there are 99 managers
so 50 will leave
leabing 49 managers out of the 50 remaining people
49/50 = 98%
(99 - x)/(100-x) =98/100
9900-100x = 9800-98x
-2x = -100
x = 50
check:
now there are 99 managers
so 50 will leave
leabing 49 managers out of the 50 remaining people
49/50 = 98%
Dawn
thanks Reiny