Asked by Amy
completely factor : z^6-z^2
Answers
Answered by
Count Iblis
z^6-z^2 =
z^2 (z^4 - 1) =
z^2 (z^2 + 1) (z^2 - 1) =
z^2 (z^2 + 1)(z + 1)(z - 1)
z^2 (z^4 - 1) =
z^2 (z^2 + 1) (z^2 - 1) =
z^2 (z^2 + 1)(z + 1)(z - 1)
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