Asked by Mary
A piece of Nichrome wire has a radius of 8.0 10-4 m. It is used in a laboratory to make a heater that dissipates 2.00 102 W of power when connected to a voltage source of 120 V. Ignoring the effect of temperature on resistance, estimate the necessary length of wire.
Answers
Answered by
bobpursley
Can you look up the resisitivity of nichrome?
Resistance= resitivity*deltaLength/area
The resistance should be determined by the power and voltage....R=V^2 /power
Resistance= resitivity*deltaLength/area
The resistance should be determined by the power and voltage....R=V^2 /power
Answered by
Mary
Please tell me where I went wrong.
R= V^2/power
R= 120V^2/2.00x10^2
R= 72
Resistance = restivity x delta Length/ area
72 = (100x10^-8)(delta length/ pi r^2)
72 = 9100x10^-8) (delta length/ 0.000002011)
72 - (100x10^-8)*(0.000002011) = deltaL
0.000144792 = delta Length
R= V^2/power
R= 120V^2/2.00x10^2
R= 72
Resistance = restivity x delta Length/ area
72 = (100x10^-8)(delta length/ pi r^2)
72 = 9100x10^-8) (delta length/ 0.000002011)
72 - (100x10^-8)*(0.000002011) = deltaL
0.000144792 = delta Length
Answered by
bobpursley
72 * PI * (8E-4^2) * (1 / 9 100E-8) = 1.59 metes
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