Asked by Klaud
Hi, I am stop on a question that I need to use conversions for. Could someone explain to me how to do this?
How many grams of SO3 could be formed from 1.2 x 10^22 atoms of O?
How many grams of SO3 could be formed from 1.2 x 10^22 atoms of O?
Answers
Answered by
DrBob222
Technically, none because you ALSO need S. :-).
You have 1.2 x 10^22 atoms of O. How many moles is that? Since there are 6.022 x 10^23 atoms in a mole, we must have
1.2 x 10^22/6.02 x 10^22 = about 0.02 moles O. How many moles S must we have? That will be 1/3 x 0.02 = 0.0067
Grams SO3 in 0.0067 moles SO3 is moles x molar mass or about 0.53 grams. You should go through, check all of my work, and use atomic masses and molar masses that you pick from the periodic table.
You have 1.2 x 10^22 atoms of O. How many moles is that? Since there are 6.022 x 10^23 atoms in a mole, we must have
1.2 x 10^22/6.02 x 10^22 = about 0.02 moles O. How many moles S must we have? That will be 1/3 x 0.02 = 0.0067
Grams SO3 in 0.0067 moles SO3 is moles x molar mass or about 0.53 grams. You should go through, check all of my work, and use atomic masses and molar masses that you pick from the periodic table.
Answered by
Klaud
My teacher taught me any of that o.o
Answered by
DrBob222
Then you didn't need any of this? If not, wasted your time and mine.