Question

Solve the system of two equations using substitution.
y=2+3x
4x−3y=−16(1 point)
Responses

(−2, −4)
left parenthesis negative 2 comma negative 4 right parenthesis

(2, 8)
left parenthesis 2 comma 8 right parenthesis

(−2, 4)
left parenthesis negative 2 comma 4 right parenthesis

(2, 10)

Answer 1

First, we'll substitute the expression for y from the first equation into the second equation:

4x - 3(2 + 3x) = -16
4x - 6 - 9x = -16
-5x - 6 = -16
-5x = -10
x = 2

Now that we know x = 2, we can substitute it back into the first equation to find y:

y = 2 + 3(2)
y = 2 + 6
y = 8

So the solution to the system of equations is (2, 8). Answer: (2, 8)