Asked by mike
You wish to prepare an aqueous solution of glycerol, C3H5(OH)3, in which the mole fraction of the solute is 0.093. How many grams of glycerol must you combine with 425 grams of water to make this solution? What is the molality of the solution?
PLEASE HELP!
PLEASE HELP!
Answers
Answered by
DrBob222
Do you know what the mole fraction is?
X<sub>gly</sub>=(n<sub>ly</sub>/(n<sub>g</sub>+ n<sub>H2O</sub>.
You know grams water, convert that to moles. You know moles glycerol = grams/molar mass and you know molar mass. You know X<sub>glycerol</sub> = 0.093.
Solve for grams glycerol which is the only unknown.
After finding the moles glycerol, molality can be calculated from the definition of molality.
m = moles solute/kg solvent.
Post your work if you get stuck.
X<sub>gly</sub>=(n<sub>ly</sub>/(n<sub>g</sub>+ n<sub>H2O</sub>.
You know grams water, convert that to moles. You know moles glycerol = grams/molar mass and you know molar mass. You know X<sub>glycerol</sub> = 0.093.
Solve for grams glycerol which is the only unknown.
After finding the moles glycerol, molality can be calculated from the definition of molality.
m = moles solute/kg solvent.
Post your work if you get stuck.
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