Asked by Lori

Write a complete solution to each problem.
If the length of a rectangle is 3 feet longer than the width and
the diagonal I s 15 feet, then what are the length and width?

I do not understand how to solve this problem. Can someone help me?
Thanks.
Answered by Anonymous
12x9
Answered by PsyDAG
Use the Pythagorean theorem.

Hypotenuse^2 = sum of squares of other two sides

Let x = length, then width = x - 3

15^2 = x^2 + (x-3)^2

Does this help?