Question 1 A)We will use the distance formula to find the lengths of each side of the rectangle.
Side AB: √((4-1)^2 + (7-7)^2) = √3^2 + 0^2 = 3 units
Side BC: √((4-4)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
Side CD: √((1-1)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
Side DA: √((1-1)^2 + (7-(-4))^2) = √0^2 + 11^2 = 11 units
Perimeter = 3 + 11 + 11 + 11 = 36 units
Answer: The perimeter of rectangle ABCD is 36 units.
Question 2 A)We will use the distance formula to find the lengths of each side of the rectangle.
Side EF: √((4-6)^2 + (9-9)^2) = √2^2 + 0^2 = 2 units
Side FG: √((4-4)^2 + (-5-9)^2) = √0^2 + 14^2 = 14 units
Side GH: √((6-4)^2 + (-5-(-5))^2) = √2^2 + 0^2 = 2 units
Side HE: √((6-6)^2 + (9-(-5))^2) = √0^2 + 14^2 = 14 units
Perimeter = 2 + 14 + 2 + 14 = 32 units
Answer: The perimeter of rectangle EFGH is 32 units.
Question 3 A)We will use the distance formula to find the lengths of each side of the quilt.
Side AB: √((1-1)^2 + (-1-4)^2) = √0^2 + 5^2 = 5 feet
Side BC: √((-3-1)^2 + (-1-(-1))^2) = √4^2 + 0^2 = 4 feet
Side CD: √((-1-(-3)^2 + (4-(-1))^2) = √2^2 + 5^2 = √4 + 25 = 5.8 (rounded to nearest tenth) feet
Side DA: √((1-(-1)^2 + (4-4)^2) = √2^2 + 0^2 = 2 feet
Perimeter = 5 + 4 + 5.8 + 2 = 16.8 feet
Answer: The perimeter of the quilt is 16.8 feet.
Question 4 A)Using the distance formula to find the lengths of each side of the house.
Side AB: √((6-6)^2 + (-6-12)^2) = √0^2 + 18^2 = 18 yards
Side BC: √((-4-6)^2 + (-6-(-6))^2) = √(-10)^2 + 0^2 = 10 yards
Side CD: √((-4-(-4)^2 + (12-(-6))^2) = √0^2 + 18^2 = 18 yards
Side DA: √((6-(-4)^2 + (12-12)^2) = √10^2 + 0^2 = 10 yards
Perimeter = 18 + 10 + 18 + 10 = 56 yards
Answer: The perimeter of the outside of the house is 56 yards.
Question 5 A)Using the distance formula to find the lengths of each side of the backyard.
Side AB: √((-1-(-11)^2 + (10-10)^2) = √10^2 + 0^2 = 10 feet
Side BC: √((-1-(-1)^2 + (-10-10)^2) = √0^2 + 20^2 = 20 feet
Side CD: √((-11-(-1)^2 + (-10-10)^2) = √10^2 + 0^2 = 10 feet
Side DA: √((-11-(-11)^2 + (10-10)^2) = √0^2 + 0^2 = 0 feet (as it is a single point)
Perimeter = 10 + 20 + 10 + 0 = 40 feet
Answer: The perimeter of the backyard is 40 feet.
Question 1 A)Find the perimeter of rectangle ABCD, with vertices A(1,7), B(4,7), C(4,−4), and D(1,−4).(1 point) $$ units Question 2 A)Find the perimeter of rectangle EFGH, with vertices E(6,9) and F(4,9), G(4,−5), and H(6,−5).(1 point) $$ units Question 3 A)William is getting ready to enter his quilt into a competition at the state fair. Before he enters the quilt, he needs to stitch the top of the quilt to the backing. He created a map of the quilt with the coordinates A(1,4), B(1,−1), C(−3,−1), and D(−1,4). Each unit on the coordinate plane represents 1 foot. Find the perimeter of the quilt in order to determine how much thread William will need to stitch the quilt to the backing.(1 point) $$ feet Question 4 A)A contractor is building a new house. She creates a map with the coordinates A(6,12), B(6,−6), C(−4,−6), and D(−4,12). Each unit on the coordinate plane represents 1 yard. What is the perimeter of the outside of the house?(1 point) $$ yards Question 5 A)A student wants to find the perimeter of their backyard. The student creates a map of their backyard with following coordinates A(−11,10), B(−1,10), C(−1,−10), and D(−11,10). Each unit on the coordinate plane represents 1 foot. Solve to find the perimeter.(1 point) $$ feet
7 answers
wrong
I apologize for the error. Let me recalculate the perimeters:
Question 1 A)
Using the distance formula to find the lengths of each side:
AB: √((4-1)^2 + (7-7)^2) = √3^2 = 3 units
BC: √((4-4)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
CD: √((1-1)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
DA: √((1-4)^2 + (7-7)^2) = √3^2 = 3 units
Perimeter = 3 + 11 + 11 + 3 = 28 units
Answer: The perimeter of rectangle ABCD is 28 units.
Question 2 A)
EF: √((4-6)^2 + (9-9)^2) = √2^2 = 2 units
FG: √((4-4)^2 + (-5-9)^2) = √14^2 = 14 units
GH: √((6-4)^2 + (-5-(-5))^2) = √2^2 = 2 units
HE: √((6-6)^2 + (9-(-5))^2) = √14^2 = 14 units
Perimeter = 2 + 14 + 2 + 14 = 32 units
Answer: The perimeter of rectangle EFGH is 32 units.
Question 3 A)
AB: √((1-1)^2 + (-1-4)^2) = √5^2 = 5 units
BC: √((-3-1)^2 + (-1-(-1))^2) = √4^2 = 4 units
CD: √((-1-(-3))^2 + (4-(-1))^2) = √4^2 + 5^2 = √16 + 25 = √41 feet
DA: √((1-(-1))^2 + (4-4)^2) = √2^2 = 2 units
Perimeter = 5 + 4 + √41 + 2 = 11 + √41 feet
Answer: The perimeter of the quilt is 11 + √41 feet.
Question 4 A)
AB: √((6-6)^2 + (-6-12)^2) = √18^2 = 18 yards
BC: √((-4-6)^2 + (-6-(-6))^2) = √10^2 = 10 yards
CD: √((-4-(-4))^2 + (12-(-6))^2) = √18^2 = 18 yards
DA: √((6-(-4))^2 + (12-12)^2) = √10^2 = 10 yards
Perimeter = 18 + 10 + 18 + 10 = 56 yards
Answer: The perimeter of the outside of the house is 56 yards.
Question 5 A)
AB: √((-1-(-11))^2 + (10-10)^2) = √10^2 = 10 feet
BC: √((-1-(-1))^2 + (-10-10)^2) = √20^2 = 20 feet
CD: √((-1-(-11))^2 + (-10-10)^2) = √10^2 = 10 feet
DA: √((-11-(-1))^2 + (10-10)^2) = √10^2 = 10 feet
Perimeter = 10 + 20 + 10 + 10 = 50 feet
Answer: The perimeter of the backyard is 50 feet.
Question 1 A)
Using the distance formula to find the lengths of each side:
AB: √((4-1)^2 + (7-7)^2) = √3^2 = 3 units
BC: √((4-4)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
CD: √((1-1)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
DA: √((1-4)^2 + (7-7)^2) = √3^2 = 3 units
Perimeter = 3 + 11 + 11 + 3 = 28 units
Answer: The perimeter of rectangle ABCD is 28 units.
Question 2 A)
EF: √((4-6)^2 + (9-9)^2) = √2^2 = 2 units
FG: √((4-4)^2 + (-5-9)^2) = √14^2 = 14 units
GH: √((6-4)^2 + (-5-(-5))^2) = √2^2 = 2 units
HE: √((6-6)^2 + (9-(-5))^2) = √14^2 = 14 units
Perimeter = 2 + 14 + 2 + 14 = 32 units
Answer: The perimeter of rectangle EFGH is 32 units.
Question 3 A)
AB: √((1-1)^2 + (-1-4)^2) = √5^2 = 5 units
BC: √((-3-1)^2 + (-1-(-1))^2) = √4^2 = 4 units
CD: √((-1-(-3))^2 + (4-(-1))^2) = √4^2 + 5^2 = √16 + 25 = √41 feet
DA: √((1-(-1))^2 + (4-4)^2) = √2^2 = 2 units
Perimeter = 5 + 4 + √41 + 2 = 11 + √41 feet
Answer: The perimeter of the quilt is 11 + √41 feet.
Question 4 A)
AB: √((6-6)^2 + (-6-12)^2) = √18^2 = 18 yards
BC: √((-4-6)^2 + (-6-(-6))^2) = √10^2 = 10 yards
CD: √((-4-(-4))^2 + (12-(-6))^2) = √18^2 = 18 yards
DA: √((6-(-4))^2 + (12-12)^2) = √10^2 = 10 yards
Perimeter = 18 + 10 + 18 + 10 = 56 yards
Answer: The perimeter of the outside of the house is 56 yards.
Question 5 A)
AB: √((-1-(-11))^2 + (10-10)^2) = √10^2 = 10 feet
BC: √((-1-(-1))^2 + (-10-10)^2) = √20^2 = 20 feet
CD: √((-1-(-11))^2 + (-10-10)^2) = √10^2 = 10 feet
DA: √((-11-(-1))^2 + (10-10)^2) = √10^2 = 10 feet
Perimeter = 10 + 20 + 10 + 10 = 50 feet
Answer: The perimeter of the backyard is 50 feet.
5 is worng
I see the mistake in question 5. Let me recalculate the perimeter:
Question 5 A)
AB: √((-1-(-11))^2 + (10-10)^2) = √10^2 = 10 feet
BC: √((-1-(-1))^2 + (-10-10)^2) = √20^2 = 20 feet
CD: √((-1-(-11))^2 + (-10-10)^2) = √20^2 = 20 feet
DA: √((-11-(-11))^2 + (10-10)^2) = √0^2 = 0 (since it's a single point)
Perimeter = 10 + 20 + 20 = 50 feet
Answer: The correct perimeter of the backyard is 50 feet.
Question 5 A)
AB: √((-1-(-11))^2 + (10-10)^2) = √10^2 = 10 feet
BC: √((-1-(-1))^2 + (-10-10)^2) = √20^2 = 20 feet
CD: √((-1-(-11))^2 + (-10-10)^2) = √20^2 = 20 feet
DA: √((-11-(-11))^2 + (10-10)^2) = √0^2 = 0 (since it's a single point)
Perimeter = 10 + 20 + 20 = 50 feet
Answer: The correct perimeter of the backyard is 50 feet.
A)Find the perimeter of rectangle ABCD, with vertices A(1,7), B(4,7), C(4,−4), and D(1,−4).(1 point)
Responses
33 units
33 units
28 units
28 units
12 units
12 units
16 units
16 units
Question 2
A)Find the perimeter of rectangle ABCD, with vertices A(−8,3), B(−1,3), C(−1,−6), and D(−8,−6).(1 point)
Responses
30 units
30 units
32 units
32 units
63 units
63 units
36 units
36 units
Question 3
A)Find the perimeter of rectangle LMNO, with vertices L(−2,−1), M(−5,−1), N(−5,−6), and O(−2,−6).(1 point)
Responses
24 units
24 units
15 units
15 units
16 units
16 units
20 units
20 units
Question 4
A)A local park is building a new playground and needs to know how much fencing to buy. The park authority creates a map of the area with the coordinates A(−5,10), B(1,10), C(1,−12), and D(−5,−12). Each unit on the coordinate plane represents 1 yard. Solve to find out how many yards of fencing is needed (the perimeter).(1 point)
Responses
56 yards
56 yards
16 yards
16 yards
12 yards
12 yards
72 yards
72 yards
Question 5
A)A restaurant is building an outside seating area. The owner created a map with the coordinates A(−11,11), B(−3,11), C(−3,1), and D(−11,1). Each unit on the coordinate plane represents 1 foot. Solve to find out how many feet of wall material they will need to build the new area (the perimeter).(1 point)
Responses
52 feet
52 feet
36 feet
36 feet
40 feet
40 feet
80 feet
Responses
33 units
33 units
28 units
28 units
12 units
12 units
16 units
16 units
Question 2
A)Find the perimeter of rectangle ABCD, with vertices A(−8,3), B(−1,3), C(−1,−6), and D(−8,−6).(1 point)
Responses
30 units
30 units
32 units
32 units
63 units
63 units
36 units
36 units
Question 3
A)Find the perimeter of rectangle LMNO, with vertices L(−2,−1), M(−5,−1), N(−5,−6), and O(−2,−6).(1 point)
Responses
24 units
24 units
15 units
15 units
16 units
16 units
20 units
20 units
Question 4
A)A local park is building a new playground and needs to know how much fencing to buy. The park authority creates a map of the area with the coordinates A(−5,10), B(1,10), C(1,−12), and D(−5,−12). Each unit on the coordinate plane represents 1 yard. Solve to find out how many yards of fencing is needed (the perimeter).(1 point)
Responses
56 yards
56 yards
16 yards
16 yards
12 yards
12 yards
72 yards
72 yards
Question 5
A)A restaurant is building an outside seating area. The owner created a map with the coordinates A(−11,11), B(−3,11), C(−3,1), and D(−11,1). Each unit on the coordinate plane represents 1 foot. Solve to find out how many feet of wall material they will need to build the new area (the perimeter).(1 point)
Responses
52 feet
52 feet
36 feet
36 feet
40 feet
40 feet
80 feet
Question 1:
To find the perimeter of rectangle ABCD, we calculate the distance between each pair of points and sum them up.
AB: √((4-1)^2 + (7-7)^2) = √3^2 = 3 units
BC: √((4-4)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
CD: √((1-1)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
DA: √((1-4)^2 + (7-7)^2) = √3^2 = 3 units
Perimeter = 3 + 11 + 11 + 3 = 28 units
Therefore, the perimeter of rectangle ABCD is 28 units.
Question 2:
Using the same approach as question 1:
Perimeter = 32 units
Therefore, the perimeter of rectangle ABCD with vertices A(−8,3), B(−1,3), C(−1,−6), and D(−8,−6) is 32 units.
Question 3:
Perimeter = 16 units
Therefore, the perimeter of rectangle LMNO with vertices L(−2,−1), M(−5,−1), N(−5,−6), and O(−2,−6) is 16 units.
Question 4:
Perimeter = 16 yards
Therefore, the park needs 16 yards of fencing for the playground.
Question 5:
Perimeter = 40 feet
Therefore, the restaurant will need 40 feet of wall material to build the new outside seating area.
To find the perimeter of rectangle ABCD, we calculate the distance between each pair of points and sum them up.
AB: √((4-1)^2 + (7-7)^2) = √3^2 = 3 units
BC: √((4-4)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
CD: √((1-1)^2 + (-4-7)^2) = √0^2 + 11^2 = 11 units
DA: √((1-4)^2 + (7-7)^2) = √3^2 = 3 units
Perimeter = 3 + 11 + 11 + 3 = 28 units
Therefore, the perimeter of rectangle ABCD is 28 units.
Question 2:
Using the same approach as question 1:
Perimeter = 32 units
Therefore, the perimeter of rectangle ABCD with vertices A(−8,3), B(−1,3), C(−1,−6), and D(−8,−6) is 32 units.
Question 3:
Perimeter = 16 units
Therefore, the perimeter of rectangle LMNO with vertices L(−2,−1), M(−5,−1), N(−5,−6), and O(−2,−6) is 16 units.
Question 4:
Perimeter = 16 yards
Therefore, the park needs 16 yards of fencing for the playground.
Question 5:
Perimeter = 40 feet
Therefore, the restaurant will need 40 feet of wall material to build the new outside seating area.
3 answers