Asked by leanne
Calculate DHo for the oxidation of nitric oxide to nitrogen dioxide,
2 NO(g) + O2(g) --> 2 NO2(g),
from the following data:
DHof[NO(g)] = +90.25 kJ
DHof[NO2(g)] = +33.18 kJ
im confused...can someone help me.
2 NO(g) + O2(g) --> 2 NO2(g),
from the following data:
DHof[NO(g)] = +90.25 kJ
DHof[NO2(g)] = +33.18 kJ
im confused...can someone help me.
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