Asked by Anonymous
how to calculate the oxidation state for 'cr' in K2CRO4 ?
Answers
Answered by
DrBob222
You need to learn how to use the caps key. That's K2CrO4.
All compounds must add to zero with oxidation numbers.
K + +1
O = -2
(2*+1) + (Cr) + 4(-2) = 0
2+Cr-8 = 0
Cr-6 = 0
Cr = 6
All compounds must add to zero with oxidation numbers.
K + +1
O = -2
(2*+1) + (Cr) + 4(-2) = 0
2+Cr-8 = 0
Cr-6 = 0
Cr = 6
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