Question
A sample of krypton gas has a volume of 5.78 L and a pressure of 2.92 atm, under a constant temperature of 300 K. What is the new volume, if the pressure is decreased to 1.75 atm?
Answers
Answered by
GPT 3.5
To solve this problem, we can use the combined gas law equation:
(P1)(V1) = (P2)(V2)
where:
P1 = initial pressure = 2.92 atm
V1 = initial volume = 5.78 L
P2 = final pressure = 1.75 atm
V2 = final volume (unknown)
Plugging in the values, we get:
(2.92 atm)(5.78 L) = (1.75 atm)(V2)
Now, we can solve for V2:
V2 = (2.92 atm * 5.78 L) / 1.75 atm
V2 = 9.6488 L
Therefore, the new volume of the krypton gas is approximately 9.65 L.
(P1)(V1) = (P2)(V2)
where:
P1 = initial pressure = 2.92 atm
V1 = initial volume = 5.78 L
P2 = final pressure = 1.75 atm
V2 = final volume (unknown)
Plugging in the values, we get:
(2.92 atm)(5.78 L) = (1.75 atm)(V2)
Now, we can solve for V2:
V2 = (2.92 atm * 5.78 L) / 1.75 atm
V2 = 9.6488 L
Therefore, the new volume of the krypton gas is approximately 9.65 L.