Question

A sample of krypton gas at a pressure of 0.825 atm and a temperature of 27.0 °C, occupies a volume of 14.7 liters. If the gas is allowed to expand at constant temperature to a volume of 24.7 liters, the pressure of the gas sample will be
atm.

Answer 1

To find the final pressure of the gas sample, we can use the ideal gas law equation:

P1V1 = P2V2

Where:
P1 = initial pressure = 0.825 atm
V1 = initial volume = 14.7 L
P2 = final pressure (unknown)
V2 = final volume = 24.7 L

Plugging in the values:

(0.825 atm)(14.7 L) = P2(24.7 L)

Solving for P2:

0.825 atm * 14.7 L = P2 * 24.7 L
12.1275 = 24.7 P2
P2 = 12.1275 / 24.7
P2 ≈ 0.492 atm

Therefore, the pressure of the gas sample when it expands to a volume of 24.7 liters is approximately 0.492 atm.