Asked by Scott
Two people push on a crate. Person 1 pushes in the positive X direction with a force of 25N. The second person pushes in the negative X direction at an angle of 15 degrees below the horizontal with a magnitude of 18.5N the box moves with uniform velocity. What is the force of friction between the box and floor?
Answers
Answered by
bobpursley
break up the negative x direction into components:
Vertical: 18.5sin15 upward
horizontal: 18.5cos15 in neg x direction
25-18.6cos15-friction=mass*acceleration=0
solve for friction force.
Vertical: 18.5sin15 upward
horizontal: 18.5cos15 in neg x direction
25-18.6cos15-friction=mass*acceleration=0
solve for friction force.
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