Asked by Lyss

To push a 25.0kg crate up a frictionless surface incline angled at 25 degrees to the horizontal, a worker exerts a force of magnitude 209N parallel to the incline. As the crate slides 1.50m, how much work is done on they crate by (a) the worker's applied force, (b) the gravitational force on the crate, and (c) the normal force exerted by the incline on the crate? (d) what is the total work done?

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Answered by bobpursley
work: 209*1.5 joules total
normal force=mgSin25
gravitational force on crate=mg
workers force=209

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