Asked by Ray

A block of wood with volume V floats in water with 0.68V submerged. In oil the block floats with 0.86V of its volume submerged.

What's the density of the wood?

Answers

Answered by drwls
All you need to answer that is the amount submerged in water, and the density of water.

According to Archimedes Principle:
(Water density) * 0.68 V
= (wood density)* V
Cancel out the V and use the density of water
1.00 g/cm^3 * 0.68 = wood density
Answered by ryan
so you are telling that .68V = (Wood density)*V.....What if .40V(say) is submerged, then will it be .40V = (Wood density)*V ????......Ur theory is wrong.....
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