Asked by Bob Dylan
The monthly revenue achieved by selling x wristwatches is figured to be x(40-0.2x)dollars. The wholesale cost of each watch is $32.
a. How many watches need to be sold each month to achieve a profit (revenue-cost) of $50?
for this part I did
x(40-.2x)-32x=50
I got 99.5 so I rounded it to 100
I'm not sure if a is right and I can't figure how to do b and c.
Perhaps for b you do the vertex -b/2a?
but I get 30 which can't be right.
b. What is the maximum revenue this firm can earn?
c. How many wristwatches should the firm sell to maximize profit?
a. How many watches need to be sold each month to achieve a profit (revenue-cost) of $50?
for this part I did
x(40-.2x)-32x=50
I got 99.5 so I rounded it to 100
I'm not sure if a is right and I can't figure how to do b and c.
Perhaps for b you do the vertex -b/2a?
but I get 30 which can't be right.
b. What is the maximum revenue this firm can earn?
c. How many wristwatches should the firm sell to maximize profit?
Answers
Answered by
Reiny
first of all, 100 can't be right.
100(40-20) - 32(100) = -1200 and not 50
You would be solving
-.2x^2 +8x - 50 = 0
multiply by -5
x^2 - 40x + 250 = 0
x = 32.25 or x = 7.75 OR 32 or 8
check: if x=8
8(40-.2(8)) - 32(8) = 51.2 close enough
if x = 32
32(40-.2(32)) - 32(32) = 51.2 , ok
Your profit equation is
Profit = x(40 - .2x) - 32x
= -.2x^2 + 8x
You are probably studying the parabola.
isn't the above a parabola opening downwards?
Wouldn't the vertex give you all the information you need?
What method have you learned to find the vertex ?
100(40-20) - 32(100) = -1200 and not 50
You would be solving
-.2x^2 +8x - 50 = 0
multiply by -5
x^2 - 40x + 250 = 0
x = 32.25 or x = 7.75 OR 32 or 8
check: if x=8
8(40-.2(8)) - 32(8) = 51.2 close enough
if x = 32
32(40-.2(32)) - 32(32) = 51.2 , ok
Your profit equation is
Profit = x(40 - .2x) - 32x
= -.2x^2 + 8x
You are probably studying the parabola.
isn't the above a parabola opening downwards?
Wouldn't the vertex give you all the information you need?
What method have you learned to find the vertex ?
Answered by
Bob Dylan
Perhaps for b you do the vertex -b/2a?
but I get 30 is that right?
but I get 30 is that right?
Answered by
Bob Dylan
I can't understand how part a. could be either 8 or 32. How could it be more than one answer?
Answered by
Reiny
if your profit function is
-.2x^2 + 8x
then the value of -b/(2a) = -8/(2(-.2)) = 20 (you had 30)
then if x=20
maximum profit = 20(40 - .2(20) - 32(20) = 80
As to your last question, doesn't every parabola have the same y value for 2 different x values, except the x value of the vertex ?
Didn't I show above that both 8 and 32 produce a profit of appr. 50 ??
-.2x^2 + 8x
then the value of -b/(2a) = -8/(2(-.2)) = 20 (you had 30)
then if x=20
maximum profit = 20(40 - .2(20) - 32(20) = 80
As to your last question, doesn't every parabola have the same y value for 2 different x values, except the x value of the vertex ?
Didn't I show above that both 8 and 32 produce a profit of appr. 50 ??
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