Asked by Z32
Evaluate the integral by interpreting it in terms of areas as 0 goes to 12 |2x - 7|dx?
This is my work so far:
2x-7=0
x=7/2
slope = 2; y-int = (0, -7)
Area of a triangle is 1/2BH.
This is my work so far:
2x-7=0
x=7/2
slope = 2; y-int = (0, -7)
Area of a triangle is 1/2BH.
Answers
Answered by
bobpursley
I can't make sense of what you did. If you want areas, you have to do it in two integrals (triangles)
x goes from 0 to 3.5
INT (7-2x) dx
Area=1/2 b H=1/2 3.5 *7
and x goes from 3.5 to 12
int (2x-7)dx
area=1/2 b H= 1/2 (12-3.5)(24-7)
x goes from 0 to 3.5
INT (7-2x) dx
Area=1/2 b H=1/2 3.5 *7
and x goes from 3.5 to 12
int (2x-7)dx
area=1/2 b H= 1/2 (12-3.5)(24-7)
Answered by
Z32
I added the two areas up and got 84.5 which is the correct. Thanks!
Answered by
Z32
One quick question, for the "area=1/2 b H= 1/2 (12-3.5)(24-7)", how did you get the 24?
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