Question
Evaluate the integral by interpreting it in terms of areas.
bounds from -1 to 0.
3+sqrt(1−x2) dx
bounds from -1 to 0.
3+sqrt(1−x2) dx
Answers
y=sqrt(1-x^2) is the equation for the top half of a circle of radius 1.
So, this would be a rectangle + 1/4 circle
So, this would be a rectangle + 1/4 circle
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0
(3 +sqrt(1 − x2)) dx
−1