Question
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find out the time at which the rocket will reach its max, to the nearest 100th of a second.
y, equals, minus, 16, x, squared, plus, 163, x, plus, 138
y=−16x
2
+163x+138
y, equals, minus, 16, x, squared, plus, 163, x, plus, 138
y=−16x
2
+163x+138
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