Question
What is the gas pressure inside the box shown in the figure?
I have a picture but website wouldn't allow me to post the link for the picture.
So I am trying my best to describe it.
it is a u-shape tube and it is holding mercury in it. One side has 16cm of mercury and other side has 6cm.
what i did was p_gas:
101300+(9.81*13600*.16*.06)..doesn't work
I have a picture but website wouldn't allow me to post the link for the picture.
So I am trying my best to describe it.
it is a u-shape tube and it is holding mercury in it. One side has 16cm of mercury and other side has 6cm.
what i did was p_gas:
101300+(9.81*13600*.16*.06)..doesn't work
Answers
drwls
There should be mercury in both sides of the tube, with a higher column height on the side opposite to the side with the gas.
The gas pressure equals
P= (mercury density) g h,
where h is the difference in the mecruty column heights.
You do not have to add 101300 (atmosheric pressure) to get the absolute pressure with a u-tube manometer such as this.
P = 9.81 m/s^2*13600 kg/m^3*(.16-.06) m
The gas pressure equals
P= (mercury density) g h,
where h is the difference in the mecruty column heights.
You do not have to add 101300 (atmosheric pressure) to get the absolute pressure with a u-tube manometer such as this.
P = 9.81 m/s^2*13600 kg/m^3*(.16-.06) m
ana
i got 13341.6 ...it is incorrect
Annie
i figured it out..thanks for helping me
ana
Annie, how can you say that...it is my question i am still working on it
Annie
sorry Ana... i missed typed it...again i apologize
bec
difference between height is 10 cm so use 0.1 instead of 0.6 and you should get 88000
Matthew
Hey, so are we sure this is the answer guys?
Genward
bro why did you say that. clearly, you are wrong. I am struggling with my physics problem and u think that's a joke?