Question

What is the expected freezing point of a 3.50 m aqueous solution of BaCl2 (Kfp=1.86C/m)? What is the boiling point (Kbp=0.512C/m? & which is affected to the greater extent, the boiling point or the freezing point?

Answer 1

Just look at the constants, freezing point depression is bigger.

FP=orig - 1.86*3.50*3
the three comes from the three ions per molecule.